THE APEX TIMES
Cincinnati’s receiver totaled 155 yards and two touchdown catches in the Bengals’ 43-36 win, earning his first career AFC Offensive Player of the Week honor.
Tee Higgins has been named the AFC Offensive Player of the Week for his performance in the Bengals’ 43-36 Week 8 win over the Tennessee Titans.
In that game, Higgins recorded 10 receptions for 155 receiving yards and two touchdown catches. His 155 receiving yards led all players across the NFL in Week 8, and his 10 catches tied for the third-most.
Both of Higgins’ touchdown receptions came in the second half. He first hauled in a 17-yard scoring pass early in the third quarter to push Cincinnati’s lead to 20-13. He then added an 18-yard touchdown catch with 1:17 remaining in the fourth quarter, setting up the game-tying PAT.
The 155-yard outing ranks among the biggest of Higgins’ career. According to the Bengals, it was his third-highest receiving yard total in a game, and his 10 catches were his fourth-highest.
The award marks Higgins’ first career AFC Offensive Player of the Week selection. It also adds to Cincinnati’s run of weekly honors in 2026, with the team noting prior weekly recognitions earned by Evan McPherson, Joe Burrow, and Ryan Rehkow.